Finding g(x) when f(x) and fg(x) are given:
Given f(x) = 2x + 1 and fg(x) = 6x + 5, find g(x)
fg(x) = 6x + 5
2g(x) + 1 = 6x + 5
2g(x) = 6x + 5 - 1
g(x) = (6x + 4)/2
g(x) = 3x + 2
Finding f(x) when g(x) and fg(x) are given:
Given g(x) = 3x - 9 and fg(x) = 6x - 11, find f(x)
fg(x) = 6x - 11
f(3x - 9) = 6x - 11
For this one, find the inverse in g(x). It is one of the easiest ways to solve this question.
g(x) = y
3x - 9 = y
3x = y + 9
x = (y + 9)/3
g-1(x) = (x + 9)/3
Why do I ask to find the inverse? If you combine g(x) with g-1(x), it combines to get an identity function. What are identity functions used for? If you combine an identity function, I with any function, f(x), it will get that function back, f(x).
fg[g-1(x)] = 6[(x+9)/3] - 11
f(x) = 2(x + 9) - 11
f(x) = 2x + 18 - 11
f(x) = 2x + 7
See, easy as that!
I'm a cute 14 years old boy, nice to meet you! My hobbies include writing fictional stories, composing songs, playing the piano, computer games, swimming and online games as well as maths solving and maths proving. Favorite authors include James Petterson, John Grisham and James Dashner. I'm good at swimming too! Read this blog for tons of sweet information!
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